(5p-15)/p^2=(1/p)-(2/p)

Solution for (5p-15)/p^2=(1/p)-(2/p) equation:

D( p )

p = 0

p^2 = 0

p = 0

p = 0

p^2 = 0

p^2 = 0

1*p^2 = 0 // : 1

p^2 = 0

p = 0

p in (-oo:0) U (0:+oo)

(5*p-15)/(p^2) = 1/p-(2/p) // - 1/p-(2/p)

(5*p-15)/(p^2)-(1/p)+2/p = 0

(5*p-15)/(p^2)-p^-1+2/p = 0

(5*p-15)/(p^2)-1/p+2/p = 0

(p*(5*p-15))/(p*p^2)+(-1*p^2)/(p*p^2)+(2*p^2)/(p*p^2) = 0

p*(5*p-15)-1*p^2+2*p^2 = 0

4*p^2+2*p^2-15*p = 0

6*p^2-15*p = 0

6*p^2-15*p = 0

3*p*(2*p-5) = 0

2*p-5 = 0 // + 5

2*p = 5 // : 2

p = 5/2

3*p*(p-5/2) = 0

(3*p*(p-5/2))/(p*p^2) = 0

(3*p*(p-5/2))/(p*p^2) = 0 // * p*p^2

3*p*(p-5/2) = 0

( 3*p )

3*p = 0 // : 3

p = 0

( p-5/2 )

p-5/2 = 0 // + 5/2

p = 5/2

p in { 0} 

p = 5/2